Top Java Interview Questions you Must Know

Java Interview Question – Java is one of the most widely used programming languages in the world, making it a popular choice for developers and employers alike. If you’re preparing for a Java job interview, it’s important to have a good understanding of the language and be able to answer some common Java interview questions. In this article, we’ll cover some of the most frequently Java Interview Questions and provide tips on how to answer them.


Now lets get into business of Java Interview Questions.

1. What is Java?

This is a basic question that most Java interviewers will ask. Java is a programming language and computing platform that is used to develop applications. It was first released in 1995 and has since become one of the most popular programming languages in the world.

2 What are the features of Java?

Java has several features that make it popular among developers, including:

  • Object-oriented programming
  • Platform independence
  • Automatic memory management
  • Security
  • Multi-threading
  • Exception handling

3. What is the difference between JDK, JRE, and JVM?

JDK (Java Development Kit) is a software development kit that is used to develop Java applications. It includes tools such as the Java compiler and debugger.

JRE (Java Runtime Environment) is a software bundle that includes the JVM (Java Virtual Machine) and other components required to run Java applications.

JVM (Java Virtual Machine) is a software program that runs Java bytecode. It converts bytecode into machine code that can be executed by the computer.

4. What is the difference between an abstract class and an interface?

An abstract class is a class that cannot be instantiated. It can have both abstract and concrete methods. An abstract class is used to provide a base implementation for its subclasses.

An interface is a collection of abstract methods that are used to define a contract for a class. Classes can implement one or more interfaces, but they cannot extend multiple classes.

5. What is the difference between a final, finally, and finalize?

Final is a keyword that is used to declare a variable, method, or class that cannot be changed.

Finally is a keyword that is used in a try-catch block to specify a block of code that should be executed regardless of whether an exception is thrown or not.

Finalize is a method that is called by the garbage collector to clean up an object before it is destroyed.

Here are some additional Java interview questions you can include in your article:

  1. What are the differences between ArrayList and LinkedList in Java?
  2. What is a constructor in Java and what is its purpose?
  3. What is the difference between the equals() method and == operator in Java?
  4. How does exception handling work in Java? Can you give an example?
  5. What is the purpose of the synchronized keyword in Java?
  6. What is the difference between an interface and an abstract class in Java?
  7. What is the purpose of the final keyword in Java?
  8. What is the difference between public, private, and protected access modifiers in Java?
  9. What is the difference between a static and non-static method in Java?
  10. What is the difference between a checked and an unchecked exception in Java?

Some JAVA programming questions



1. Write a Java program to find the factorial of a given number.

import java.util.Scanner;

public class Factorial {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print(“Enter a number: “);
int num = input.nextInt();
int factorial = 1;
for (int i = 1; i <= num; i++) {
factorial *= i;
}
System.out.println(“Factorial of ” + num + ” is: ” + factorial);
}
}

In this program, we first take input from the user using the Scanner class. We then calculate the factorial of the given number using a for loop, and finally print the result to the console using the println method.

2. Write a Java program to find the factorial of a given number.

public class BubbleSort {
public static void main(String[] args) {
int[] array = { 5, 1, 12, -5, 16, 2, 12, 14 };
bubbleSort(array);
System.out.println(“Sorted Array: ” + Arrays.toString(array));
}

public static void bubbleSort(int[] array) {
int n = array.length;
int temp = 0;
for (int i = 0; i < n; i++) {
for (int j = 1; j < (n – i); j++) {
if (array[j – 1] > array[j]) {
// Swap elements
temp = array[j – 1];
array[j – 1] = array[j];
array[j] = temp;
}
}
}
}
}

In this program, we have an integer array array that we want to sort using bubble sort algorithm. The bubbleSort method takes the array as input and performs the sorting operation.

The algorithm works by comparing adjacent elements in the array and swapping them if they are not in the correct order. The largest element will “bubble up” to the end of the array in each iteration, so the algorithm needs to iterate through the array n-1 times (where n is the length of the array) to ensure that all elements are in their correct order.

After sorting the array, we print it to the console using Arrays.toString(array).

3. Write a Java program to reverse a string using recursion.

public class StringReverseRecursion {

public static void main(String[] args) {
String originalString = “Hello World!”;
String reversedString = reverseString(originalString);
System.out.println(“Original String: ” + originalString);
System.out.println(“Reversed String: ” + reversedString);
}

public static String reverseString(String str) {
if (str.isEmpty()) {
return str;
}
return reverseString(str.substring(1)) + str.charAt(0);
}

}

In this program, the reverseString() method takes a String as input and recursively reverses it. The base case is when the input string is empty, in which case the method simply returns the empty string. Otherwise, the method calls itself with the substring of the input string starting from the second character, and then concatenates the first character of the input string to the end of the result. This process continues recursively until the entire input string is reversed.

4. Implement a Java program to find the nth Fibonacci number

import java.util.Scanner;

public class Fibonacci {

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print(“Enter the value of n: “);
int n = sc.nextInt();

// call the fibonacci method to find the nth fibonacci number
int fib = fibonacci(n);

// print the result
System.out.println(“The ” + n + “th Fibonacci number is ” + fib);
}

// method to find the nth fibonacci number using recursion
public static int fibonacci(int n) {
if (n <= 1) {
return n;
}
return fibonacci(n – 1) + fibonacci(n – 2);
}
}


In this program, the user is prompted to enter the value of n. The fibonacci() method is then called with the value of n as its parameter. The fibonacci() method uses recursion to find the nth Fibonacci number. If n is less than or equal to 1, the method returns n. Otherwise, it recursively calls itself with the values of n-1 and n-2 until it reaches the base case.

5. Implement a Java program to find the maximum and minimum elements in an array of integers.

To find the maximum and minimum elements in an array of integers using Java, you can follow these steps:

  1. Create an integer array of n elements.
  2. Initialize the array with some values.
  3. Set the first element of the array as the maximum and minimum.
  4. Iterate through the array and compare each element with the maximum and minimum values. If an element is greater than the maximum, set it as the new maximum. If it is less than the minimum, set it as the new minimum.
  5. After the iteration, the maximum and minimum values will be stored in the variables.
  6. Display the maximum and minimum values.

Here’s the Java code to implement the above steps:

public class MaxMinArray {
public static void main(String[] args) {
int[] arr = {10, 20, 5, 15, 25};
int max = arr[0];
int min = arr[0];

for (int i = 1; i < arr.length; i++) {
if (arr[i] > max) {
max = arr[i];
}
if (arr[i] < min) {
min = arr[i];
}
}

System.out.println(“Maximum element in the array: ” + max);
System.out.println(“Minimum element in the array: ” + min);
}
}

6. Implement a Java program to find the maximum and minimum elements in an array of integers

public class MaxMinElement {
public static void main(String[] args) {
int[] arr = {4, 9, 2, 7, 5, 8, 1, 3, 6};
int max = arr[0];
int min = arr[0];

for (int i = 1; i < arr.length; i++) {
if (arr[i] > max) {
max = arr[i];
}
if (arr[i] < min) {
min = arr[i];
}
}

System.out.println(“Maximum element in the array is: ” + max);
System.out.println(“Minimum element in the array is: ” + min);
}
}

In this program, we first define an array of integers with some values. Then, we initialize two variables max and min with the first element of the array. We then iterate over the array using a for loop, comparing each element with max and min, and updating these variables as necessary.

At the end of the loop, we print out the values of max and min to the console, which will be the maximum and minimum elements in the array, respectively.

7. Write a Java program to check if a given string is a palindrome

import java.util.Scanner;

public class PalindromeChecker {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print(“Enter a string: “);
String inputString = scanner.nextLine();
if (isPalindrome(inputString)) {
System.out.println(inputString + ” is a palindrome.”);
} else {
System.out.println(inputString + ” is not a palindrome.”);
}
}

public static boolean isPalindrome(String inputString) {
inputString = inputString.toLowerCase().replaceAll(“[^a-zA-Z0-9]”, “”);
int length = inputString.length();
for (int i = 0; i < length / 2; i++) {
if (inputString.charAt(i) != inputString.charAt(length – i – 1)) {
return false;
}
}
return true;
}
}

This program takes a string input from the user and checks if it’s a palindrome by removing all non-alphanumeric characters and comparing the first and last characters, the second and second-to-last characters, and so on until the middle of the string is reached. If all characters match, the string is considered a palindrome.

8. Implement a Java program to perform binary search on a sorted array of integers

import java.util.Arrays;

public class BinarySearchExample {
public static void main(String[] args) {
int[] array = {2, 5, 7, 12, 15, 20, 30};
int key = 15;
int result = binarySearch(array, key);
if (result == -1) {
System.out.println(“Element not found”);
} else {
System.out.println(“Element found at index ” + result);
}
}

public static int binarySearch(int[] array, int key) {
int low = 0;
int high = array.length – 1;

while (low <= high) {
int mid = (low + high) / 2;
if (array[mid] == key) {
return mid;
} else if (array[mid] < key) {
low = mid + 1;
} else {
high = mid – 1;
}
}

return -1;
}
}

In the example above, we first define an array of integers and a key element to search for. Then we call the binarySearch function which implements the binary search algorithm. The function takes two arguments, an array of integers and a key element to search for, and returns the index of the key element if it’s found, or -1 if it’s not found.


Inside the binarySearch function, we define two variables low and high that represent the lowest and highest indexes of the array. We then enter a loop that continues until low becomes greater than high, which means the key element is not found in the array. In each iteration of the loop, we calculate the middle index of the array using the formula (low + high) / 2, and compare the value at the middle index to the key element. If they are equal, we return the middle index. If the value at the middle index is less than the key element, we set low to mid + 1, since the key element must be in the right half of the array. If the value at the middle index is greater than the key element, we set high to mid - 1, since the key element must be in the left half of the array.

Once the loop terminates, we return -1 to indicate that the key element is not found in the array.

9. Write a Java program to find the sum of all the elements in an array of integers

public class ArraySum {
public static void main(String[] args) {
int[] arr = {5, 3, 8, 6, 2};
int sum = 0;

for (int i = 0; i < arr.length; i++) {
sum += arr[i];
}

System.out.println(“The sum of the elements in the array is: ” + sum);
}
}

In this program, we first declare an integer array arr with some values. We then declare an integer variable sum and initialize it to 0.

Next, we use a for loop to iterate through each element of the array and add it to the sum variable. Finally, we print the value of sum to the console, which gives us the sum of all the elements in the array.

10. Implement a Java program to convert a decimal number to binary

import java.util.Scanner;

public class DecimalToBinary {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print(“Enter a decimal number: “);
int decimal = input.nextInt();

int[] binaryArray = new int[32];
int index = 0;

while (decimal > 0) {
binaryArray[index++] = decimal % 2;
decimal /= 2;
}

System.out.print(“Binary representation: “);
for (int i = index – 1; i >= 0; i–) {
System.out.print(binaryArray[i]);
}
}
}

In this program, we take input from the user as a decimal number and then use a while loop to convert it to binary. We keep dividing the decimal number by 2 and store the remainder (either 0 or 1) in an array. After the loop ends, we print the binary representation by iterating over the array from the highest index to the lowest index.

Quick Links: Read more tips for students

Feel Free to drop your questions and other thoughts in the comment section below.

Follow Us on Facebook

Follow US on Twitter

 

 



Select the platform to share this

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top